Posted by andi telaumbanua on Feb 17, 2018 in
Matematika |
Carilah Turunan pertama dari fungsi berikut:
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y = (cos x)^x
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y = x^cosx
Jawab:
Use Logarithmic differentiation
1. ln y = ln (cos x)^x
ln y = x ln(cos x)
d/dx(ln y)= d/dx(x ln cosx)
d/dy(ln y)dy/dx = d/dx(x ) (ln cosx) + x d/dx(ln cos x)
1/y dy/dx = ln cos x + x 1/cosx d/dx(cos x)
1/y dy/dx = ln cos x + x 1/cosx (- sinx)
1/y dy/dx = ln cos x – x sin x/cos x
1/y dy/dx = ln cos x – x tanx
dy/dx = y ( ln cos x – x tan x )
dy/dx = (cos x)^x ( ln cos x – x tan x )
ln y = ln x^cosx
ln y = cos x lnx
d/dx(ln y) = d/dx(cos x ln x)
d/dy(ln y) dy/dx = d/dx(cos x ) (ln x) + cos x d/dx(ln x)
1/y dy/dx = – sin x ln x + cos x 1/x
1/y dy/dx = cos x/x – sin x ln x
dy/dx = y ( cos x/x – sin x ln x)
dy/dx = x^cos x ( cos x/x – sin x ln x)
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