Turunan pertama dari y = [(x+1)/(x-1)]^2

Posted by andi telaumbanua on Feb 13, 2018 in Matematika |
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Tentukan turunan pertama dari y = [(x+1)/(x-1)]^2 !

Jawab:

Gunakan aturan rantai

Misalkan :

u = (x+1)/(x-1)

maka:

du/dx = [ 1(x-1) – (x+1)1 ] / (x-1)^2

du/dx = -2 /(x-1)^2

Sehingga : y = u^2

maka :

dy/du = 2u

dy/du = 2[(x+1) / (x-1)]

dy/du = (2x+2) / (x-1)

Maka:

dy/dx = ( dy/du ) (du/dx)

dy/dx = [(2x+2)/(x-1)] [-2 / (x-1)^2]

dy/dx = (-4x – 4) / (x-1)^3

for more clear writing please click the link below

Tentukan turunan pertama dari y = ((x+1)/(x-1))^2 !

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