sin^(-1) ( √3/2 )
Posted by andi telaumbanua on Feb 10, 2018 in Matematika |
Tentukanlah nilai dari sin^(-1) ( √3/2 ) !
Jawab:
Karena f^(-1) x = y ↔ f(y) = x
Maka: sin^(-1) x =y ↔ sin y = x untuk : – π/2 ≤ x ≤ π/2
Misalkan : sin^(-1) ( √3/2 ) = a
maka: sin a = ( √3/2 )
maka: a = arcsin ( √3/2 )
a = 60°
atau a = π/6
sehingga sin^(-1) ( √3/2 ) = a = 60° = π/6
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